Question

The density of the thin rod of length l increases uniformly from λ at one end to 2λ at the other end. Determine the moment of inertia about an axis perpendicular to the rod through its geometrical center.

          The density of the thin rod of length l increases uniformly from λ at one end to 2λ at the other end. Determine the moment of inertia about an axis perpendicular to the rod through its geometrical center.
        

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The density of the thin rod of length l increases uniformly from λ at one end to 2λ at the other end. Determine the moment of inertia about an axis perpendicular to the rod through its geometrical center.
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Transcript

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00:01 Calculate the moment of inertia about an axis through the geometric center of the rod.
00:05 So we can say that we're going to select a differential element of the rod of length dx.
00:10 So this would be the differential length essentially.
00:13 And it would be at a distance x from the center of the rod here.
00:18 This dash line represents the essentially the axis of rotation.
00:23 Because the mass density changes uniformly from the initial.
00:31 Mass density we can say that here we can say that here x we have the initial mass density at rather we can say x equals rather negative l over 2 and then we can say that this will be three times the initial mass density at x equaling l over 2 so here we can say that the mass then mass density function lambda this would be equal to 2 times lambda multiplied by one over one, rather one plus x over l.
01:17 And we're essentially finding the mass of the differential element.
01:23 So we can say dm is equaling lambda dx.
01:27 This is going to be equal to two lambda one plus x over l multiplied by dx.
01:37 And so now we're going to use equation 1016...
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