Question

The diagram shows triangle AOB, where O is the origin and point C lies on the straight line AB, divided by BC: CA = 2: 3. M is the midpoint of straight line OA. Determine: y A (9, 4) M O x C B (-1, -6) A. Point M and Point C [3 marks] B. Straight line equation of CM [3 marks] C. Distance of CM [1 mark] D. Area of quadrilateral OMCB [3 marks]

          The diagram shows triangle AOB, where O is the origin and point C lies on the straight line AB, divided by BC: CA = 2: 3. M is the midpoint of straight line OA. Determine:
y A (9, 4) M O x C B (-1, -6) A. Point M and Point C [3 marks] B. Straight line equation of CM [3 marks] C. Distance of CM [1 mark] D. Area of quadrilateral OMCB [3 marks]

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The diagram shows triangle AOB, where O is the origin and point C lies on the straight line AB, divided by BC: CA = 2: 3. M is the midpoint of straight line OA. Determine:
y A (9, 4) M O x C B (-1, -6) A. Point M and Point C [3 marks] B. Straight line equation of CM [3 marks] C. Distance of CM [1 mark] D. Area of quadrilateral OMCB [3 marks]

Added by Irene Y.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

05/16/2024

Step 1

Since the ratio of BC:CA is 2:3, we can use the section formula to find the coordinates of C: C = ((3 * B_x + 2 * A_x) / 5, (3 * B_y + 2 * A_y) / 5) C = ((3 * (-1) + 2 * 9) / 5, (3 * 8 + 2 * 4) / 5) C = (15 / 5, 28 / 5) C = (3, 5.6) Now, we need to find the Show more…

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The diagram shows triangle AOB, where O is the origin and point C lies on the straight line AB, divided by BC: CA = 2:3. M is the midpoint of the straight line OA. Determine: A. Point M and Point C [3 marks] B. Straight line equation of CM [3 marks] C. Distance of CM [1 mark] D. Area of quadrilateral OMCB [3 marks]

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