The equation of motion of a particle is given by s(t) = 2t^3 + t^2 - t + 1 where s is in meters and time t is in seconds. a) Find the velocity when t = 3 seconds. b) Find the acceleration when t = 3 seconds.
Added by Katherine E.
Step 1
Given the position function \( s(t) = 2t^3 + t^2 - t + 1 \), the velocity function is the derivative of the position function, which is \( v(t) = 6t^2 + 2t - 1 \). Substitute \( t = 3 \) into the velocity function: \( v(3) = 6(3)^2 + 2(3) - 1 = 6(9) + 6 - 1 = 54 + Show more…
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