the kinetic energy of electrons are emitted when light with wavelength 410nm shines on the surface of a sodium is? work function of sodium = 2.8 eV
Added by Richard H.
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Given: wavelength = 410 nm To convert from nanometers to meters, divide by 10^9. wavelength = 410 nm / (10^9 m/nm) = 4.1 x 10^-7 m Show more…
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Light of frequency 0.930 × 10^15 Hz illuminates a sodium surface. The ejected photoelectrons are found to have a maximum kinetic energy of 1.57 eV. Calculate the work function of sodium. Planck's constant is 6.63 × 10^-34 J · s. Answer in units of eV.
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The work function of sodium metal is $2.3 \mathrm{eV}$. What is the longestwavelength light that can cause photoelectron emission from sodium? At threshold, the photon energy just equals the energy required to tear the electron loose from the metal. In other words, the electron's $\mathrm{KE}$ is zero and so $h f=\varphi$. Since $f=c / \lambda$ $$ \begin{array}{c} \phi=\frac{h \mathrm{c}}{\lambda} \\ (2.3 \mathrm{eV})\left(\frac{\left(1.602 \times 10^{-19} \mathrm{~J}\right.}{1.00 \mathrm{eV}}\right)=\frac{\left(6.63 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right)\left(2.998 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)}{\lambda} \\ \lambda=5.4 \times 10^{-7} \mathrm{~m} \end{array} $$
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