00:01
In this question, it is about using converging mirror, okay, converging mirror to observe the moon.
00:09
Okay, this is the moon, and then light comes from the moon, then it focuses on some point.
00:20
Okay, yeah, so we want to find out the diameter of the moon's image.
00:27
Okay, all right, so solution.
00:41
So this is this problem involves the mirror.
00:48
So we'll be using the mirror equation, which is 1 over s plus over s prime equals to 1 over f.
00:56
The focal length of the mirror is 1 .2 meters.
01:01
The distance between the object distance, s is equal to 3 .8 times 10 to 8 meters.
01:16
Then f is 1 .2 meters so s prime is 1 over s prime is equal to 1 over 1 .2 minus 1 over 3 .8 times 10 to the 8 so this is approximately 1 over 1 .2 okay so s prime is going to be 1 .2 meters okay, right.
02:04
Then to find the diameter of the moon's image, it will be using the formula...