The national distribution of fatal work injuries in a...

The national distribution of fatal work injuries in a country is shown in the table to the right under National %. You believe that the distribution of fatal work injuries is different in the western part of the country and randomly select 6231 fatal work injuries occurring in that region. At alpha equals 0.025, can you conclude that the distribution of fatal work injuries in the west is different from the national distribution? Complete parts a through d below. Cause National % Western Frequency Transportation 44% 2895 Equipment 17% 1156 Assaults 14% 805 Falls 13% 747 Harmful fumes 9% 531 Fires 3% 97 - Calculate the test statistic to THREE decimal places and decide whether to reject or fail to reject the null hypothesis.

Transcript

00:01 Hi, i'm rabbit and i'm here to help you answer your question.

00:03 Now let me bring up your question here.

00:06 In the question here, we are going to discuss about the hybrid testing.

00:11 Here, we want to test the null hypothesis.

00:14 At all that, the proportion for the coast national for the transportation, it will equal to the 44%.

00:24 Our condition will be the p1 and it will equal to the 044 and the p2.

00:31 For the equipment equal to the 17 % will be the 017 and the p2 b3 you could be assumed equal to the 14 % and the p4 it will equal to the 13 % and the p5 equal to the zerpon 09 % and the p6 we get equal to for the fire it will be the 3 % will be the zonzo 3 and then we're given the data for the total 6 ,231 and we have the frequency for all of them.

01:14 Now let me draw the table here.

01:17 We have 1, 2, 3, 4, 5 and 6.

01:28 And the first one for the transportation i denoted by the t.

01:32 For the equipment i will call as an e, assount, i will be a 8.

01:37 Phones we have f, hamphoon, f will be arch, and then f stand from the fires will be fire here and we have the observed value denoted by the o and we have for the transportation we have the total 2 ,895 for the equipment we get the 1156 and for the ozone to equal to the 800 and 5 for the phone will be the 747 for the hamphun fung equal to the 531 and for the fire equal to the 97 and the next time i need to find the expected count for each categories i will call this one as the e and to find expected count i will have the total here and then i take the 6 2 3 1 and then it times on the corresponding probability will be the 0 .44 and if we do it i have the 6231 times when the 014 equal to the 2744 similarly we have the 6231 times with the corresponding probability and then we get equal to the 6231 times 0 .17 equal to the 1059 point 27 then we have the 6231 times 0 .14.

03:09 Now we get 6231 times 0 .14 equal to the 872 .34.

03:17 And 6231 10 with the 0 .13.

03:22 And then we get equal to the 810 .03.

03:30 And 6231.

03:31 And 6231 times under 0 .03.

03:34 Then we get equal to the 560 point 79 and the last one 6231 times good the 0 .03 then we get equal to the 186 .93...

Question

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