00:01
Hi, so we are going to use clous clapperan equation here to solve for the vapor pressure of bromine at the given temperature.
00:11
So, first solution.
00:14
Closius clapper in equation, that's ln of p2 over p1, is equivalent to negative delta h of vaporization over r, constant, and then multiplied by 1 over t .2.
00:30
This is the temperature at p2 minus 1 over t 1 the temperature at p 1 so our unknown here is p 2 and then we know the boiling point of brumin and the pressure of at normal boiling point if it's not given then we could assume that it's just 1 atm so 1 atm for p 1 and then negative 30 this is kilo joles per mole so we need to convert this to joles because r is in terms of joles.
01:08
1 kilo -chol, that's equivalent to 1 ,000 joules over r, that's 8 .314, choles per mole, kelvin.
01:20
And then t2.
01:21
We have 28 .5 degrees celsius, so we need to add 273 for this to be in.
01:28
Sorry, let me just rewrite.
01:32
We write this one.
01:35
Okay, that should be the unit.
01:37
Kelvin minus 1 over 508 .8 plus conversion factor 273.
01:49
Okay, so that means we can now cancel some minutes.
01:54
Kilchols here, and then jules and moles, and kelvin will also be canceled.
02:01
So on the right side of the equation, we'll have negative 3608.
02:06
0 .37 multiplied by 3 .0286 times 10 to the negative 4.
02:15
This will be unit less and then ln of the re -write this...