Given that f(x) = ax^3 + 63x^2 + 152x + b, and it passes through (-2, b), we substitute x = -2 into the polynomial to find b.
\[f(-2) = a(-2)^3 + 63(-2)^2 + 152(-2) + b = b\]
\[b = -8a + 252 - 304 + b\]
\[0 = -8a - 52\]
Since the b's cancel out, we're left with an
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