The position of a particle moving along a coordinate axis is given by s(t) = t^3 - 9t^2 + 24t + 4 for t ≥ 0. What is the velocity of the object after 3 seconds? What is the acceleration of the object after 2 seconds?
Added by Jill G.
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So, we have: v(t) = \frac{d}{dt}(t^3 - 9t^2 + 24t + 4) Now, let's find the derivative: v(t) = 3t^2 - 18t + 24 Show more…
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