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Hi.
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In this video we're going to do some calculus 1.
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So i'm only going to do number 1 because if you want all of these answered, you should ask them at separate questions because they are different questions.
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And doing them all would be too much for one problem.
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So i'll do number 1.
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So in this one we have a velocity function 1 minus 2t.
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And we want to find the distance traveled in the first second of motion.
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So the velocity in the first second goes from 1 to negative 1, right? so it's going to move to the right, and then by the end of the first second, it's going to be moving to the left with the velocity negative 1.
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So what we need to do to calculate this is actually split up the integral.
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It's going to go from 0 to 1 half because that's when the turnaround happens, when 1 minus 2 t is equal to 0, so t is 1 1 1⁄2.
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And then we'll integrate 1 minus 2t, and then we subtract the integral from 1 half to 1 of 1 minus 2t.
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So we have t minus t squared from 0 to 1⁄2m, minus t squared from 0 to 1⁄2...