The function is:
$S(t) = 700,000(0.9)^t$
Now, we find the derivative:
$\frac{dS}{dt} = 700,000 \cdot \ln(0.9) \cdot (0.9)^t$
Now, we can find the rate of depreciation after 1 year, 5 years, and 10 years by plugging in the respective values of t:
After 1
Show more…