00:01
Hi, now we are going to find the mean, median and mode.
00:05
Now, we change the class intervals as 15 .5 to 20 .5, 20 .5 to 25 .5, 25 .5 to 30 .5, 30 .5 to 35 .5, 35 .5 to 40 .5, 40 .5 to 45 .5, 45 .5 to 50 .5 and the given frequencies are 2, 6, 15, 10, 8, 7.
00:56
So, their total n will be 50 and the corresponding mid values are 18, 23, 28, 33, 38, 43, 48.
01:10
Here, i assume that the assumed mean is 33 and here the class interval h is 5 and then we found d is equal to x minus a divide by h.
01:23
So, the corresponding values of d are minus 3, minus 2, minus 1, 0, 1, 2, 3 and then we have to find f multiplied by d and this value will be minus 6, minus 12, minus 15, 0, 8, 14, 6 and from the given table we have the cumulative frequency is 2, 8, 23, 33, 41, 48, 50.
01:47
Now, we know that mean is equal to a plus summation f d divide by n multiplied by h.
02:01
So, now we have to substitute the corresponding values in this, then the mean x bar will be equal to 33 minus 5 divide by 50 multiplied by 5.
02:12
On further simplification, this will be equal to 33 minus 0 .5 that is 32 .5.
02:21
Therefore, we have the mean for the given data is 32 .5 and next we are going to calculate the median.
02:30
Now, here the median class will be the value of n by 2 observation.
02:48
Here the value of n is 50, so n by 2 will be 25.
02:57
So, this will be the value of 25th observation.
03:08
So, we have the median class is 30 .5 to 35 .5.
03:19
Here we have the value of l is 30 .5 and n is equal to 50...