The switch was open for a long time before it is closed at $t = 0$ s. Find $I_2(t)$ and $V_2(t)$ for all $t$. $C_1 = 7 \mu F$, $C_2 = 10 \mu F$, and $V = 7 V$. (a) (b) \begin{array}{|c|c|c|c|c|} \hline & t = 0^- & t = 0^+ & t = \infty & \text{Unit} \\ \hline I_2 & 0 & .35 & .234 & A \\ V_2 & 3.5 & 3.5 & 4.66 & V \\ \hline \end{array} \begin{array}{|c|c|c|c|c|} \hline & t > 0 & & & \\ \hline I_2(t) & (.234 & ) + ( .35 - .234 )e^{1} & x (t - 0) & A \\ V_2(t) & (4.66 & ) + (3.5 - 4.66 )e^{ } & x (t - 0) & V \\ \hline \end{array}
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Since the switch was open for a long time, the capacitors would have been fully charged to the initial voltage (V0). Therefore, V0 = 7V. Show more…
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