00:01
The task is to find the solution to the given differential equation and it will be 1 minus cosine of x and then it is going to be d -y and in the denominator it is d -x.
00:14
So this value will be equals to y times sine of x.
00:18
So let us rewrite this equation in separable form and it will be here d -y, then it is going to be y and this value is equal to to sine of x and in the denominator it is 1 minus cosine of x and here it will be d x.
00:38
So if we simplify this problem further by substituting u, so u will be here equals to 1 minus cosine of x and then we can write that if we differentiate this expression then the value of d u will be equal to it is sine of x and then it will be d x and then it will be d x.
00:59
So let us substitute this value in the above expression and the above expression can be simplified as dy and here it is y.
01:09
Now this is equal to here as du and then it will be u.
01:14
So now if we integrate both the sides then we will be having here ln and then it is absolute value of y and that is equal to ln and here it will be absolute value of it is 1 minus cosine of x.
01:29
Which was the value of u.
01:31
So if we simplify this expression further, then it can be written as y, and it is e -raged -to -the -power -c...