00:01
So here we can say that first the leaf spring can hold a certain force.
00:12
We're going to label this f.
00:13
This would be equalling the coefficient, the spring constant rather, of the leaf spring, so k sub l, k sub leaf, multiplied by the compression distance or y initial.
00:28
So this would be equalling the spring constant of the leaf spring, 5 .25 times.
00:34
10 to the fifth newtons per meter multiplied by 0 .50 meters and the force then is going to be equaling 2 .625 times 10 to the 5th newton's now at this point we can say that the the total force applied on the spring is going to be 5 times 10 to the 5th so we can say force total on the spring is equaling 5 times 10 to the 5th newton we can then say that the additional force, additional force on the leaf spring is equaling the total force minus the force that the leaf spring can hold.
01:25
And so this is going to be equaling 5 minus 2 .625, so 2 .375 times 10 to the 5th newtons.
01:33
Now, at this point, at this point, we know that this force will be shared by the leaf spring and the helper spring.
01:47
So we can say that the compression of the spring for this additional force, we can say that compression for the additional force is equaling 2 .375 times 10 to the 5th newton's.
02:08
And again, this would be divided by the spring constant of the leaf spring plus the spring constant of the helper spring.
02:19
And so we can say that the additional compression, we can just say delta y additional, will be equaling for the denominator.
02:34
It'll be 5 .25 times 10 to the 5th newtons per meter for the leaf spring plus the spring constant for the helper spring.
02:51
3 .6 times 10 to the 5th newtons per meter.
02:57
And for the numerator, again, 2 .375 times 10 to the 5th newtons.
03:03
And this is equaling 0 .268 meters...