Is the following statement "Since ( lim _{n ightarrow infty}left(frac{frac{1}{n sqrt{n^{6}+3}}}{frac{1}{n^{2}}} ight)=0 ) and ( sum_{n=1}^{infty} frac{1}{n^{2}} ) is convergent, by Limit Comparison Test ( sum_{n=1}^{infty} frac{1}{n sqrt{n^{6}+3}} ) is convergent." true or false? Select one: True False
Added by Saadet Burcu T.
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First, we need to find the limit of the given expression: \( \lim _{n \rightarrow \infty}\left(\frac{\frac{1}{n \sqrt{n^{6}+3}}}{\frac{1}{n^{2}}}\right) \) This simplifies to: \( \lim _{n \rightarrow \infty}\left(\frac{n^{2}}{n \sqrt{n^{6}+3}}\right) \) Now, we Show more…
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