00:01
Finding the left remand sum on the interval from 0 to 1 using n equals 5 subintervals, we'll begin by finding the width of each subinterval using delta x equals b minus a over n, where a and b come from the end points of our intervals, so 1 minus 0 over 5 or 1 5th.
00:24
Certainly you can make that point 2 if you like as well.
00:29
Because we're doing the left remon sum, we start at the vote.
00:32
Very left end point of our interval, in this case, at x equals zero.
00:37
And that means that f of zero will be the height of our first rectangle, and the width will be one -fifth.
00:44
Because every rectangle has a height of one -fifth, actually we has a width of one -fifth.
00:49
To find the height, we move one -fifth unit to the right from the previous rectangle.
00:54
So if x -equal zero gave us the height for our first rectangle, x -equals one -fifth is used.
01:03
To find the height of our second rectangle.
01:05
So f of one -fifth is the height of the second rectangle.
01:09
Adding one -fifth, we get f of two -fifths for the height of the third rectangle...