Question

Two vectors are given as follows: $\vec{B} = -2\vec{i} - 8\vec{j} + 2\vec{k}$ $\vec{C} = -5\vec{i} - 2\vec{j} - 3\vec{k}$ The angle between vectors $\vec{B}$ and $\vec{C}$, in degrees, is closest to: A) 112 B) 68 C) 90 D) 128

Name: two vectors are given as follows vecb 2veci 8vecj 2veck vecc 5veci 2vecj 3veck the angle between vectors vecb and vecc in degrees is closest to a 112 b 68 c 90 d 128 68097
Uploaded: 2022-02-09T18:37:13-08:00
Duration: 2 min 40 s
Channel: Kajal Raghubanshi
Description: two vectors are given as follows vecb 2veci 8vecj 2veck vecc 5veci 2vecj 3veck the angle between vectors vecb and vecc in degrees is closest to a 112 b 68 c 90 d 128 68097

          Two vectors are given as follows:
$\vec{B} = -2\vec{i} - 8\vec{j} + 2\vec{k}$
$\vec{C} = -5\vec{i} - 2\vec{j} - 3\vec{k}$
The angle between vectors $\vec{B}$ and $\vec{C}$, in degrees, is closest to:
A) 112
B) 68
C) 90
D) 128

two vectors are given as follows vecb 2veci 8vecj 2veck vecc 5veci 2vecj 3veck the angle between vectors vecb and vecc in degrees is closest to a 112 b 68 c 90 d 128 68097

Added by Francisco Javier J.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kajal Raghubanshi

02/09/2022

Step 1

Step 1: The angle $\theta$ between two vectors $\vec{B}$ and $\vec{C}$ can be found using the dot product formula: $\vec{B} \cdot \vec{C} = |\vec{B}| |\vec{C}| \cos{\theta}$ $\cos{\theta} = \frac{\vec{B} \cdot \vec{C}}{|\vec{B}| |\vec{C}|}$ Show more…

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Two vectors are given as follows: $\vec{B} = -2\vec{i} - 8\vec{j} + 2\vec{k}$ $\vec{C} = -5\vec{i} - 2\vec{j} - 3\vec{k}$ The angle between vectors $\vec{B}$ and $\vec{C}$, in degrees, is closest to: A) 112 B) 68 C) 90 D) 128