Question

Use a geometric formula to find the area between the graphs of y = f(x) and y = g(x) over the indicated interval.\ f(x) = x, g(x) = \sqrt{9 - x^2}; \left[0, \frac{3\sqrt{2}}{2}\right]\ The area is \boxed{\text{ }} (Type an exact answer, using $\pi$ as needed.)

Name: Use a geometric formula to find the area between the graphs of y = f(x) and y = g(x) over the indicated interval.f(x) = x, g(x) = √(9 - x^2); [0, (3√(2))/(2)]The area is (Type an exact answer, using π as needed.)
Uploaded: 2022-02-23T10:39:24-08:00
Duration: 1 min 59 s
Channel: Kranti S
Description: Use a geometric formula to find the area between the graphs of y = f(x) and y = g(x) over the indicated interval.f(x) = x, g(x) = √(9 - x^2); [0, (3√(2))/(2)]The area is (Type an exact answer, using π as needed.)

          Use a geometric formula to find the area between the graphs of y = f(x) and y = g(x) over the indicated interval.\
f(x) = x, g(x) = \sqrt{9 - x^2}; \left[0, \frac{3\sqrt{2}}{2}\right]\
The area is \boxed{\text{ }} (Type an exact answer, using $\pi$ as needed.)

Use a geometric formula to find the area between the graphs of y = f(x) and y = g(x) over the indicated interval.f(x) = x, g(x) = √(9 - x^2); [0, (3√(2))/(2)]The area is (Type an exact answer, using π as needed.)

Added by Michael Y.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Kranti S

02/23/2022

Step 1

To find the points of intersection, we set f(x) equal to g(x) and solve for x: x = √(9 - x^2) x^2 = 9 - x^2 2x^2 = 9 x^2 = 9/2 x = ±√(9/2) Since the interval is [0, (3√2)/2], we only consider the positive value of x, which is √(9/2) = 3√2/2. Show more…

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Use a geometric formula to find the area between the graphs of y=f(x) and y=g(x) over the indicated interval. f(x)=x,g(x)=sqrt(9-x^(2));[0,(3sqrt(2))/(2)] The area is (Type an exact answer, using pi as needed.) Use a geometric formula to find the area between the graphs of y=f(x and y = g(x) over the indicated interval 3v2 f(x)=x,g(x)=9 - The area is (Type an exact answer, using as needed.)