00:01
In this question, we are asked to solve the given system of linear equations using the gauss jordan elimination method.
00:09
First, we need to create the augmented matrix of the system of equations.
00:13
To do that, we just need to take the coefficients in front of x, y, and z, and the right -hand sides and put them in rows.
00:23
So the roll corresponding to the first equation is 1 -9136, and the role corresponding to the second equation is 1 -9121, 4 and 5 so this is the augmented matrix of our system of equations and now we'll start doing row operations we will subtract the first row from the second row we will rewrite the first row.
00:48
You're going to get 1 negative 1, 3, 6 and then in the second row we are going to get 0 because 1 minus 1 is 0 negative 1 minus negative 1 is also 0 alright sorry, 4 minus 3 is 1 and 5 minus 6 is negative 1.
01:18
Now we will go in the reverse direction.
01:21
Now we will multiply the second row by negative 3 and add it to the first row.
01:42
We will multiply the second row by negative 3 and add it to the first row.
01:50
And what we are going to get is we will rewrite the second row 0 0.
01:55
0, 1, negative 1.
01:59
And then in the first row, we are going to get 0 times negative 3 is 0, plus 1 is 1, then 0 times negative 3 is 0 plus negative 1 is negative 1.
02:12
Then 1 times negative 3 is negative 3, and negative 3 plus 3 is going to be 0...