Use l'Hopital's Rule to evaluate the limit.\\ $\lim_{x \to \infty} \frac{13x^2 + 6x - 2}{14x^2 - 2x + 14}$ \\ $\frac{14}{13}$ \\ $1$ \\ $-\frac{13}{14}$ \\ $\frac{13}{14}$
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Step 1: Identify the form of the limit We are given the limit as x approaches infinity: lim (x->∞) (13x^2 + 6x - 2) / (14x^2 - 2x + 14) This is an indeterminate form of the type ∞/∞, which means we can apply L'Hopital's Rule. Show more…
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