00:01
In this problem, we have sine of s as 2 by 3 and sign of t as minus 1 by 3.
00:13
S is in second quadrant and t is in 4th quadrant.
00:19
So let us first find what is cos of s.
00:22
Since s is in second quadrant, cost will be negative.
00:25
This will be 1 minus sine square of s.
00:28
This comes as minus root of 5 by 3.
00:32
Similarly, cos of t will be positive since t is in fourth quadrant.
00:36
This will be 1 minus sine square of t.
00:40
This comes as root 8 by 3.
00:43
So for the first part of the problem, we have to find what is sign of s plus t.
00:48
This will be nothing but sine of s, cos of t plus cause of s into sine of t...