00:01
In this question, we are asked to determine with the given series converges or diverges by using the limit comparison test.
00:08
And to do that, we will compare it to the series bn from 10 to infinity.
00:18
And to get bn, we need to take the highest power of n in the numerator and divide that by the highest power of n in the denominator.
00:27
And we will get n -cube divided by n to the fourth.
00:32
And that simplifies to one or n.
00:34
So the series we are comparing to is the series of 1 over n, n from 10 to infinity, and we know that that series diverges by the p test, and because it's a harmonic series, p test with p being equal to 1.
00:59
Now by the limit comparison test, we need to calculate the limit as n goes to infinity of the general term of our series, which is 9 and q.
01:12
Minus 7 n squared plus 10, divide by 5 plus 2 n to the 4th, over the general term of the series bn.
01:27
So divide by 1 or n.
01:31
And we want that limit to be finite and greater than 0.
01:37
Then both series either converge or diverge at the same time.
01:44
And since the series bn diverges, this will force our source.
01:48
Series to diverge too...