00:01
In this question, we are asked to find the row reduced echelon form of the matrix a, was a given matrix.
00:07
To do that, we need to multiply the first row by negative 2 and add it to the second row, and multiply the first row by 3 and add it to the third row.
00:26
We will rewrite the first row.
00:31
In the second row we'll get 0.
00:34
5 minus 8, which is negative 3, negative 4 plus 10, which is 6, 6.
00:44
Negative 1 minus 2 which is negative 3 and 4 minus 4 which is 0 and in the third row we'll get 0 12 minus 9 is 3 negative 15 plus 9 is negative 6 3 plus 2 is 5 and 6 plus 2 is 8 now the next step would be to add the 2 row to the 3rd row we will rewrite the 5 first two rows, in the third row we'll get 0, 0, 0, 2, 8.
01:46
Now we will divide the second row by 2 and the third row by negative 3, 3rd row by 2 and the 2 and the 2 0 0 0 0 in the 2, 1 0 in the 2 in the 2 0 0 in the 3rd row...