Question

VDC1 8.0V LED1 ic R2 47Ω Q1 2N2222A U1 0.000 DC 10MOhm S3 R1 39kΩ ib Key = Space If the base is connected to the positive voltage, there is current into the base so the transistor is , so current flow from collector to emitter, so there is current through the LED. The voltmeter reads . iB = iC = LED is

Name: vdc1 80v led1 ic r2 47 q1 2n2222a u1 0000 dc 10mohm s3 r1 39k ib key space if the base is connected to the positive voltage there is current into the base so the transistor is 73195
Uploaded: 2023-11-22T19:17:23-08:00
Duration: 1 min 37 s
Channel: Supreeta N
Description: vdc1 80v led1 ic r2 47 q1 2n2222a u1 0000 dc 10mohm s3 r1 39k ib key space if the base is connected to the positive voltage there is current into the base so the transistor is 73195

          VDC1
8.0V
LED1
ic
R2
47Ω
Q1
2N2222A
U1
0.000
DC 10MOhm
S3
R1
39kΩ
ib
Key = Space
If the base is connected to the positive voltage, there is ________ current into the base so the transistor is ________, so current ________ flow from collector to emitter, so there is ________ current through the LED. The voltmeter reads ________.
iB = ________
iC = ________
LED is ________

vdc1 80v led1 ic r2 47 q1 2n2222a u1 0000 dc 10mohm s3 r1 39k ib key space if the base is connected to the positive voltage there is current into the base so the transistor is 73195

Added by Keith R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

11/22/2023

Step 1

We need to fill in the blanks based on the circuit's operation when the base is connected to a positive voltage. First, let's identify the components and their values: - VDC1 (top): 8.0V (connected to the collector side through LED1 and R2) - VDC1 (bottom left): Show more…

Show all steps

Thanks for your feedback!

VDC1 8.0V LED1 ic R2 47Ω Q1 2N2222A U1 0.000 DC 10MOhm S3 R1 39kΩ ib Key = Space If the base is connected to the positive voltage, there is ________ current into the base so the transistor is ________, so current ________ flow from collector to emitter, so there is ________ current through the LED. The voltmeter reads ________. iB = ________ iC = ________ LED is ________