Evaluate the limit: \lim_(x->6)(x^(2)-3x-18)/(x-6) Evaluate the limit: $\lim_{x\to 6} \frac{x^2-3x-18}{x-6}$
Added by Michael R.
Close
Step 1
We get $$ \frac{6^2 - 3(6) - 18}{6-6} = \frac{36 - 18 - 18}{0} = \frac{0}{0} $$ Since we get an indeterminate form, we need to simplify the expression. Show more…
Show all steps
Your feedback will help us improve your experience
Sanchit Jain and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Sanchit J.
Evaluate the limit if it exists. $$ \lim _{x \rightarrow 2} \frac{x^{2}+x-6}{x-2} $$
Limits: A Preview of Calculus
Finding Limits Algebraically
Evaluate the limit, using L'Hopital's Rule if necessary. (In Exercise 18, $n$ is a positive integer.) $$\lim _{x \rightarrow 3} \frac{x^{2}-2 x-3}{x-3}$$
Integration Techniques, L’Hopital’s Rule, and Improper Integrals
Indeterminate Forms and L’Hopital’s Rule
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD