00:01
In this problem, you were told to find f3, magnitude of f3, so that f net x was zero.
00:13
So f3 would knock out the x components of 1 and 2.
00:18
So that's the first part.
00:20
And obviously, from what i've seen, that would have been the, you're already at part e with the angle.
00:28
So that would have been done, previously had to be, found f3.
00:33
To make this true.
00:43
Then you added up all the y components.
00:49
F1y plus f2y plus f3y.
01:00
F1y being in the first quadrant is plus f2y is negative.
01:07
That was a third quarter vector.
01:11
And f3 is a second quadrant vector.
01:14
So that's a plus y component.
01:16
And this, as i can see, a couple of steps back, you also got that correct as minus 2 .04 kiloons.
01:28
Then the previous part to this angle is asking the magnitude.
01:35
Well, it is only got one component, so the magnitude is just the absolute value of that one components.
01:40
That's simple enough.
01:42
So as you correctly enter, 2 .04 kiloons.
01:45
And then you come to the angle.
01:48
And i think it's just a matter, it's just a matter of interpretation of what they're talking about in terms of an angle.
01:56
If you draw this out, this is f net, is in the negative y direction.
02:05
You've got a minus 2 .04 kilonters.
02:07
That's it.
02:08
It's the only component you hit.
02:11
So when they speak of an angle, positive angles are counterclockwise, from the plus x axis...