Use the Laplace transform to solve the initial value problem $$y''-7y'+12y = f(t), y(0) = 0, y'(0) = 0$$ where $$f(t) = \begin{cases} 0 & \text{if } 0 \le t < 3 \\ -6t + \frac{37}{2} & \text{if } t \ge 3 \end{cases}$$ Note: Use u for the step function. y(t) =
Added by Shawn P.
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$$L[y''-7y'+12y] = L[f(t)]$$ $$s^2Y(s) - sy(0) - y'(0) - 7(sY(s) - y(0)) + 12Y(s) = F(s)$$ Show more…
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