Question

Write the following in the form of $re^{i\theta}$, r = | a + bi | = $\sqrt{a^2 + b^2}$ a. 1 + $\sqrt{3}i$ b. - 2 + 2i c. -$\sqrt{3}$ - i d. $\sqrt{2}$ - $\sqrt{2}i$ e. (1 + $\sqrt{3}i$)^{12} f. 2i g. $\sqrt{3}i$ - 1 h. ($\frac{1+i}{1-i}$)$^5$

          Write the following in the form of $re^{i\theta}$, r = | a + bi | = $\sqrt{a^2 + b^2}$ 
a. 1 + $\sqrt{3}i$
b. - 2 + 2i
c. -$\sqrt{3}$ - i
d. $\sqrt{2}$ - $\sqrt{2}i$
e. (1 + $\sqrt{3}i$)^{12}
f. 2i
g. $\sqrt{3}i$ - 1
h. ($\frac{1+i}{1-i}$)$^5$

Write the following in the form of re^iθ, r = | a + bi | = √(a^2 + b^2)
a. 1 + √(3)i
b. - 2 + 2i
c. -√(3) - i
d. √(2) - √(2)i
e. (1 + √(3)i)^12
f. 2i
g. √(3)i - 1
h. ((1+i)/(1-i))^5

Added by Charles P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Thanks for your feedback!

Write the following in the form of reiÎ¸, r = |a + bi| = âˆš(a^2 + b^2) Write the following in the form of reiÎ¸, r = |a + bi| = âˆš(a^2 + b^2) a. 1 + âˆš3i b. -2 + 2i c. -âˆš3 - i d. âˆš2 - âˆš2i e. (1 + âˆš3i)^12 f. 2i g. âˆš3i - 1 h. âˆš3i