Yvonne has one copy of a gene for an X-linked dominant disease. She is fortunate to have a very mild form of the disease, which suggests that in the relevant organs, the X chromosome containing the dominant disease allele is silenced by X inactivation. If she has children with a man who does not have this allele, what will be true about her future children? Check All That Apply Her daughters will definitely get the disease allele. Her sons will definitely get the disease allele. Her children will all have a 50% chance of inheriting the dominant disease allele. Her daughters will also have a mild form of the disease because X inactivation will occur in a similar pattern between mother and daughter.
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The disease is X-linked dominant. Yvonne has one copy of the dominant allele. This means her genotype is $X^D X^d$, where $X^D$ is the chromosome with the dominant disease allele and $X^d$ is the chromosome with the recessive normal allele. The man she has Show more…
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One copy of the X chromosome is randomly inactivated in human female embryos; in each cell between the 4-cell and 32-cell stages. A woman with an inactivated recessive trait that results in her having all homozygous recessive for an X-linked dominant and unpigmented is recessive. If she has children with a man who has all normally pigmented skin, their offspring could include: - a son with all normally pigmented skin - a son with all unpigmented skin - a son with patches of pigmented and unpigmented skin
Adi S.
Couple has two offspring; one child with an autosomal recessive disease trait and one normal. What conclusions can we make about the parents? One parent must have the autosomal recessive disease. Both parents must carry the autosomal recessive disease. One parent is a carrier for the autosomal recessive disease and the other parent is normal. Both parents probably carry the autosomal recessive disease. Which of the following is generally true of an X-linked recessive pedigree? Disease affects more males than females. Pattern of skipped generations. Males are usually affected. Mothers can transmit the disease to their daughters. Which of the following genetic diseases is transmitted through autosomal recessive inheritance? Duchenne muscular dystrophy. Cystic fibrosis. Hemophilia. Huntington's disease. Diabetes mellitus type 2 can be common within a family, and yet no single gene has been identified causing the problem, although diet and exercise habits influence whether the disease develops. This disease is probably controlled by: complex gene regulation. autosomal recessive mutation. multifactorial inheritance. A 41-year-old pregnant female miscarries her first fetus. Analysis shows that the fetus had 45 chromosomes. Which of the following describes this condition? Euploidy. Triploidy. Tetraploidy. Aneuploidy. Genetic testing reveals that a woman has inherited a autosomal dominant disease gene from her mother, and yet she does not exhibit any symptoms of the disease. Which of the following could best explain this? The disease has incomplete penetrance. The disease is caused by epigenetic modifications. She is a chromosomal mosaic. She has Turner Syndrome. A healthy couple has a child with hemophilia. The couple later divorces and each remarries. Which of the following statements is correct? If the father has more children with his new wife, there is a 50% chance that his daughters will have hemophilia. If the father has more children with his new wife, there is a 50% chance that his sons will have hemophilia. If the mother has more children with her new husband, there is a 50% chance that her sons will have hemophilia. If the mother has more children with her new husband, there is a 50% chance that her daughters will have hemophilia.
X-linked traits X-linked traits are caused by genes found on the X chromosome in humans. Sex chromosomes are passed on to offspring through the law of segregation, the same as all the autosomal chromosomes. There are many different conventions for representing the alleles of X-linked traits in a Punnett square. This problem uses the following convention: The sex chromosomes are indicated with a capital X or Y. The alleles found on those chromosomes are indicated with a superscript letter next to the sex chromosome letter. For example, an X chromosome carrying a dominant allele for a trait would be represented as XA, and an X chromosome carrying a recessive allele for that trait would be represented as Xa. This problem discusses genes that are found only on the X chromosome, so no allele is listed for the Y chromosome. Duchenne muscular dystrophy (DMD) is a serious disorder that causes progressive degeneration of the muscles. DMD is caused by a recessive X-linked allele, meaning that the defective allele that causes DMD is found only on the X chromosome. People affected with DMD usually do not have children, either by choice or because the condition prevents them from doing so. For the purposes of this question, however, assume that they are able to have children. Imagine that two people are planning to have a child together. The woman is a normal female with no recessive DMD allele, and the man is normal male. Complete the Punnett square, showing the possible genotypes and phenotypes their children could have. (Note: The man's genotype has already been filled in for you. Keep in mind that in Punnett squares the dominant allele is always listed first.) Say this couple ends up having a son. What is the chance that this child has DMD? 100% 0% 50% 75% Say a woman who has DMD has many children with a man who does not have DMD. What will their children be? All of their daughters will be carriers, and all of their sons will have DMD. Neither their daughters nor their sons will have DMD. All of their daughters will have DMD, and none of their sons will. All of their daughters will have DMD, and all of their sons will be carriers.
Sri K.
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