00:01
We're asked to find the solution to the system of equations.
00:03
Each one of these equations is a line so we know that the solution is there's three options.
00:10
It could have one solution, the lines could intersect, there could be no solution, the lines would be parallel, and there could be an infinite number of solutions if the lines are the exact same.
00:21
So we're going to go ahead and solve this.
00:25
There's several ways you can do it.
00:27
You can solve it by graphing, you can solve it by elimination, you can solve it by substitution.
00:50
Substitution is best done when one of your variables is by itself with a coefficient of one.
00:57
Since we have a coefficient other than one on all all of these variables i'm not going to do substitution.
01:03
Graphing probably is not the best way to do it because elimination is probably the way you're expected to do this.
01:12
Graphing would work but it's awfully quick and we'll check it with graphing.
01:16
So we're going to solve it by elimination.
01:18
Now i'm going to focus in on my y variables.
01:21
What i want to do is i want to multiply the top equation by 2, everything by 2, so that's going to give me 8x plus 10y equals 14 and i want to multiply everything in the bottom equation by 5 and that's going to give me 15x minus 10y equals negative 60...