00:02
As for the question, the differential equation is da by dt is equal to negative ka.
00:14
Also here we have da is equal to negative ka dt.
00:23
So basically we can write this equation in this form also.
00:27
So here now integrate both sides and here we have integration integration.
00:39
D .a is equal to negative k a d t and here we have a sign of integration again.
00:52
Now further it will be written as integration da by a is equals to negative k and here we have dt.
01:03
So now on integrating it we have lna is equal to negative kt plus c.
01:11
So here we have a is equals to e raised to the power negative kt plus c.
01:25
Further it will be written as a is equals to e raised to the power c, e raised to the power negative kt.
01:34
So here where this e raised to the power c is constant.
01:44
So here we'll mark this as equation one...