00:01
In this question, we need to solve the differential equation using laplace transform.
00:05
The equation is dy over dt plus 5 times y is equals to 4 e raised to minus 3t where y0 is equals to minus 2.
00:17
So, what we are going to get? we will take, we can write this as y dash plus 5y is equals to 4 e raised to minus 3t.
00:27
Now, what i will do? i will take the laplace transform to both sides.
00:40
So, this is going to give me l of, this is a laplace operator, 5 times laplace y is equals to 4 times laplace of e raised to minus 3t.
00:56
So, we are going to use this property that the laplace of e raised to 8t is equals to 1 over s minus a and we know that laplace of y dash is given by s times y of s plus 2 and this will be plus 5 times y of s is equals to 4 over s plus 3 because here the value of a is minus 3.
01:23
So, i get s plus 3.
01:26
So, from this if i take y as common, i am going to get 5 plus s.
01:33
This is 4 over s plus 3 minus 2...