'When two lenses are used in combination; the first one forms an image that then serves as the object for the second lens The magnification of the combination is the ratio of the height of the final image to the height of the object A 20-cm-tall object is 50.0 cm to the left of a lens of focal length of magnitude 40.0 cm second lens; this one having a focal length of magnitude 60.0 cm is located 300.0 cm to the right of the first lens along the same optic axis.'
Added by Michael M.
Step 1
Step 1: Use the lens equation for the first lens with a focal length of 40 cm: \[ \frac{1}{f} = \frac{1}{p} + \frac{1}{q} \] \[ \frac{1}{40} = \frac{1}{50} + \frac{1}{q} \] Solving for q, we get: \[ q = 200 \text{ cm} \] Show more…
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When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.00 cm -tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm . A second converging lens, this one having a focal length of 60.0 cm , is located 300 cm to the right of the first lens along the same optic axis. A-Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0 cm . B-I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.
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When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.60 cm-tall object is 56.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. Enter your answers in centimeters separated by a comma.
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A 1.20-cm-tall object is 50.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300.0 cm to the right of the first lens along the same optic axis. (a) Find the location and height of the image (call it $I_1$) formed by the lens with a focal length of 40.0 cm. (b) $I_1$ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.
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