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(1 point) Express the following rectangular triple integral as a triple integral in cylindrical coordinates.\nNOTE: When typing your answers use \"th\" for $\theta$.\n$\int_{-8}^{8} \int_{0}^{\sqrt{64-x^{2}}} \int_{0}^{\sqrt{64-x^{2}-y^{2}}} 6\sqrt{x^{2}+y^{2}} dz\ dy\ dx = \int_{\theta_{1}}^{\theta_{2}} \int_{r_{1}}^{r_{2}} \int_{z_{1}}^{z_{2}} \text{________} dz\ dr\ d\theta$\n$z_{1}=$\n$z_{2}=$\n$r_{1}=$\n$r_{2}=$\n$\theta_{1}=$\n$\theta_{2}=$\nEvaluate the integral\n$\int_{-8}^{8} \int_{0}^{\sqrt{64-x^{2}}} \int_{0}^{\sqrt{64-x^{2}-y^{2}}} 6\sqrt{x^{2}+y^{2}} dz\ dy\ dx = $\n

          (1 point) Express the following rectangular triple integral as a triple integral in cylindrical coordinates.\nNOTE: When typing your answers use \"th\" for $\theta$.\n$\int_{-8}^{8} \int_{0}^{\sqrt{64-x^{2}}} \int_{0}^{\sqrt{64-x^{2}-y^{2}}} 6\sqrt{x^{2}+y^{2}} dz\ dy\ dx = \int_{\theta_{1}}^{\theta_{2}} \int_{r_{1}}^{r_{2}} \int_{z_{1}}^{z_{2}} \text{________} dz\ dr\ d\theta$\n$z_{1}=$\n$z_{2}=$\n$r_{1}=$\n$r_{2}=$\n$\theta_{1}=$\n$\theta_{2}=$\nEvaluate the integral\n$\int_{-8}^{8} \int_{0}^{\sqrt{64-x^{2}}} \int_{0}^{\sqrt{64-x^{2}-y^{2}}} 6\sqrt{x^{2}+y^{2}} dz\ dy\ dx = $\n

(1 point) Express the following rectangular triple integral as a triple integral in cylindrical coordinates.: When typing your answers use ẗhf̈or θ.∫-8^8∫0^√(64-x^2)∫0^√(64-x^2-y^2) 6√(x^2+y^2) dz dy dx = ∫θ1^θ2∫r1^r2∫z1^z2 dz dr dθz1=z2=r1=r2=θ1=θ2=the integral∫-8^8∫0^√(64-x^2)∫0^√(64-x^2-y^2) 6√(x^2+y^2) dz dy dx =

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