Question

When using partial fractions to find antiderivatives in calculus, we decompose complicated rational expressions into the sum of simpler expressions that can be integrated individually. The required decomposition is: (72)/(x(x^2+9)) = (A)/(x) + (Bx+C)/(x^2+9). A=?, B=?, and C=?

Name: when using partial fractions to find antiderivatives in calculus we decompose complicated rational expressions into the sum of simpler expressions that can be integrated individually the req 44392
Uploaded: 2023-08-30T17:58:18-08:00
Duration: 1 min 47 s
Channel: Madhur L
Description: when using partial fractions to find antiderivatives in calculus we decompose complicated rational expressions into the sum of simpler expressions that can be integrated individually the req 44392

          When using partial fractions to find antiderivatives in calculus, we decompose complicated rational expressions into the sum of simpler expressions that can be integrated individually. The required decomposition is:
(72)/(x(x^2+9)) = (A)/(x) + (Bx+C)/(x^2+9). A=?, B=?, and C=?

Added by Brian R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

08/30/2023

Step 1

Step 1: First, we start by decomposing the given rational expression into the sum of simpler expressions: (72)/(x(x^2+9)) = (A)/(x) + (Bx+C)/(x^2+9) Show more…

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When using partial fractions to find antiderivatives in calculus, we decompose complicated rational expressions into the sum of simpler expressions that can be integrated individually. The required decomposition is: (72)/(x(x^2+9)) = (A)/(x) + (Bx+C)/(x^2+9). A=?, B=?, and C=?