Question

Which is the equation for a circle with center at \( (-2,-4) \) that passes through the point \( (3,8) \) ? \[ \begin{array}{l} (x-2)^{2}+(y+4)^{2}=144 \\ (x+2)^{2}+(y+4)^{2}=144 \\ (x-2)^{2}+(y+4)^{2}=169 \\ (x+2)^{2}+(y+4)^{2}=169 \end{array} \]

          Which is the equation for a circle with center at \( (-2,-4) \) that passes through the point \( (3,8) \) ?
\[
\begin{array}{l}
(x-2)^{2}+(y+4)^{2}=144 \\
(x+2)^{2}+(y+4)^{2}=144 \\
(x-2)^{2}+(y+4)^{2}=169 \\
(x+2)^{2}+(y+4)^{2}=169
\end{array}
\]

Which is the equation for a circle with center at (-2,-4) that passes through the point (3,8) ?

(x-2)^2+(y+4)^2=144

(x+2)^2+(y+4)^2=144

(x-2)^2+(y+4)^2=169

(x+2)^2+(y+4)^2=169

Added by Tiffany O.

Precalculus Student Solutions Manual 5th

Margaret L. Lial, John Hornsby, David I.… 5th Edition

Chapter 2

Instant Answer

Solved by Expert Melissa Munoz

Step 1

Step 1: Recall the standard form of the equation of a circle with center \((h, k)\) and radius \(r\): \[ (x - h)^2 + (y - k)^2 = r^2 \] Show more…

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Which is the equation for a circle with center at \( (-2,-4) \) that passes through the point \( (3,8) \) ? \[ \begin{array}{l} (x-2)^{2}+(y+4)^{2}=144 \\ (x+2)^{2}+(y+4)^{2}=144 \\ (x-2)^{2}+(y+4)^{2}=169 \\ (x+2)^{2}+(y+4)^{2}=169 \end{array} \]