why do both ionization energy and electron affinity play a role in estimating the energy of an a

Name: why do both ionization energy and electron affinity play a role in estimating the energy of an atomic orbital to use in a molecular orbital calculation 21296
Uploaded: 2021-11-28T21:50:37-08:00
Duration: 1 min 30 s
Channel: Nicole Smina
Description: why do both ionization energy and electron affinity play a role in estimating the energy of an atomic orbital to use in a molecular orbital calculation 21296

Step 1: Understand that the energy of an atomic orbital in a molecule is influenced by how tight

Why do both ionization energy and electron affinity play a...

Nicole Smina and 86 other subject Chemistry 101 educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Key Concept

Premium Feature

Explore the core concept behind this problem.

Key Concept

Premium Feature

Explore the core concept behind this problem.

Recommended Videos

One way of estimating the electronegativity of an atom is to use an average of its ionization energy and electron affinity. Why would these two quantities, taken together, be related to electronegativity?

Chemistry: The Molecular Nature of Matter

3-10-pts-the-ionization-energy-ie-of-an-electron-from-an-atom-can-be-estimated-according-to-koopman-theorem-which-states-that-ie-en-where-en-is-the-orbital-energy-from-which-the-electron-is-01228

The ionization energy (IE) of an electron from an atom can be estimated according to Koopman's theorem which states that IE ≈ –En, where En is the orbital energy from which the electron is removed. (a) Calculate the ground state ionization energy for Heⁱ, using the simplified energy expression for hydrogenic systems. (b) Without doing any calculations, predict how IE changes in the across the series H, Heⁱ, Li²ⁱ, Be³ⁱ, B⁴ⁱ, C⁵ⁱ, N⁶ⁱ, O⁷ⁱ, F⁸ⁱ and Ne⁹ⁱ. Briefly explain reasoning behind your order.

Sri K.

for-both-atoms-and-molecules-ionization-energies-section-74-are-related-to-the-energies-of-orbital-2

For both atoms and molecules, ionization energies (Section 7.4) are related to the energies of orbitals: The lower the energy of the orbital, the greater the ionization energy. The first ionization energy of a molecule is therefore a measure of the energy of the highest occupied molecular orbital (HOMO). See the "Chemistry Put to Work" box on Orbitals and Energy. The first ionization energies of several diatomic molecules are given in electron-volts in the following table: $$ \begin{array}{ll} \hline \text { Molecule } & I_{1}(\mathrm{eV}) \\ \hline \mathrm{H}_{2} & 15.4 \\ \mathrm{~N}_{2} & 15.6 \\ \mathrm{O}_{2} & 12.1 \\ \mathrm{~F}_{2} & 15.7 \\ \hline \end{array} $$ (a) Convert these ionization energies to $\mathrm{kJ} / \mathrm{mol}$. (b) On the same plot, graph $I_{1}$ for the $\mathrm{H}, \mathrm{N}, \mathrm{O}$, and $\mathrm{F}$ atoms (Figure 7.11) and $I_{1}$ for the molecules listed. (c) Do the ionization energies of the molecules follow the same periodic trends as the ionization energies of the atoms? (d) Use molecular orbital energy-level diagrams to explain the trends in the ionization energies of the molecules.

Transcript

00:01 Okay, so one way of estimating the electronegativity is if you take the first ionization energy and you add the electron affinity and then you divide by two.

00:14 So electronegativity is the tendency to attract electrons.

00:20 So it'll be a bigger number if you attract electrons, specifically in a covalent bond.

00:24 Ionization energy is how hard it is to remove an electron.

00:31 So if it's hard to remove an electron.

00:32 So if it's hard to remove an electron, this is going to be a big positive number, and that's going to be corresponding to a higher electron negative...

Question

Why do both ionization energy and electron affinity play a role in estimating the energy of an atomic orbital to use in a molecular orbital calculation?

Question

Why do both ionization energy and electron affinity play a role in estimating the energy of an atomic orbital to use in a molecular orbital calculation?

Please give Ace some feedback