Question

Write the complex number $z = -6 - 3i$ in polar form: $z = r(cos \theta + i sin \theta)$ where \\ $r = \sqrt{45}$ and $\theta = $ \\ The angle should satisfy $0 \le \theta < 2\pi$.

          Write the complex number $z = -6 - 3i$ in polar form: $z = r(cos \theta + i sin \theta)$ where \\
$r = \sqrt{45}$ and $\theta = $ \\
The angle should satisfy $0 \le \theta < 2\pi$.

Write the complex number z = -6 - 3i in polar form: z = r(cos θ + i sin θ) where

r = √(45) and θ =

The angle should satisfy 0 ≤θ < 2π.

Added by Andrew M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Julian Wong

08/19/2022

Step 1

The magnitude of a complex number z=a+bi is given by |z| = sqrt(a^2 + b^2). In this case, a=-6 and b=-3. |z| = sqrt((-6)^2 + (-3)^2) = sqrt(36 + 9) = sqrt(45) = 3sqrt(5). Show more…

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Write the complex number z=-6-3z in polar form: z=r(cos heta +isin heta ) where r=, and B= The angle should satisfy 0<=8<2pi . Write the complex number z = -6 - 3 in polar form: z = r(cos & + sin ) where V45 and =[I The angle should satisfy 0 2