Write the equation of the plane, 2x-3y+2z=6, in intercept form and find the points where it intersects the coordinate axes
(x)/(3)+(y)/(2)+(z)/(3)=1, intercepts ={(3,0,0),(0,2,0),(0,0,3)}
-(x)/(3)-(y)/(2)-(z)/(3)=1, intercepts ={(-3,0,0),(0,-2,0),(0,0,-3)}
(x)/(3)-(y)/(2)+(z)/(3)=1, intercepts ={(2,0,0),(0,-3,0),(0,0,2)}
(x)/(3)-(y)/(2)+(z)/(3)=1, intercepts ={(3,0,0),(0,-2,0),(0,0,3)}
(x)/(3)+(y)/(2)+(z)/(3)=1, intercepts ={(2,0,0),(0,3,0),(0,0,2)}
Write the equation of the plane23y2z6in intercept form and find the points where it intersects the coordinate axes H13 + y 2 12 3 -1,intercepts={3,0,00,2,000,3}
x 3
f 12
1,intercepts{3,0,002,00,03}
312 + 2 3 13 =1,intercepts={2,0,00,3,00,0,2}
x 3
y 2 + 3 =1,intercepts={3,0,0,0-2,00,0,3} H/3 + 312 + 2 3 =1,intercepts={2,0,00,3,00,0,2}