Write the equation of the plane, $2x - 3y + 2z = 6$, in intercept form and find the points where it intersects the coordinate axes
? $\frac{x}{3} + \frac{y}{2} + \frac{z}{3} = 1$, intercepts = {(3,0,0), (0,2,0), (0,0,3)}
? $-\frac{x}{3} - \frac{y}{2} - \frac{z}{3} = 1$, intercepts = {(-3,0,0), (0,-2,0), (0,0,-3)}
? $\frac{x}{3} - \frac{y}{2} + \frac{z}{3} = 1$, intercepts = {(2,0,0), (0,-3,0), (0,0,2)}
? $\frac{x}{3} - \frac{y}{2} + \frac{z}{3} = 1$, intercepts = {(3,0,0), (0,-2,0), (0,0,3)}
? $\frac{x}{3} + \frac{y}{2} + \frac{z}{3} = 1$, intercepts = {(2,0,0), (0,3,0), (0,0,2)}