00:01
In this problem the given system of equations can be written as 2, 1, minus 5.
00:06
This is 1, minus 2, 0.
00:09
This is 3, minus 5, minus 1, times x, y, z.
00:21
This is equals to 714.
00:26
So we will write the augmented matrix to solve the problem.
00:31
Now note that augmented matrix is nothing but, so if this is a, x, b.
00:35
It is nothing but a, colon, b.
00:39
We can interchange the position.
00:41
So let us first write 1, minus 2, 0.
00:44
This is 1, 2, 1, minus 5.
00:48
This is 7.
00:50
This is 3, minus 5, minus 1.
00:53
This is 4.
00:57
Next, to solve this we will apply some transformation.
01:01
R2 as r2, minus 2r1.
01:04
R3 as r3, minus 3r1.
01:09
This is 1, minus 2, 0.
01:13
This is 1.
01:16
We multiply first row by 2 and then subtract.
01:18
So this is 0...