Question

(x - 16)(x - a) = x^2 - 5ax + b In the given equation, a and b are constants. If the equation is true for all values of x, what is the value of b?

          (x - 16)(x - a) = x^2 - 5ax + b
In the given equation, a and b are constants. If the equation is true for all values of x, what is the value of b?

Added by Elisa S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Yujie Wang

06/13/2021

Step 1

(x-16)(x-a) = x^2 - ax - 16x + 16a (x-16)(x-a) = x^2 - (a+16)x + 16a Show more…

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(x-16)(x-a)=x^(2)-5ax+b In the given equation, a and b are constants. If the equation is true for all values of x, what is the value of b ? A) 16 B) 64 C) 128 D) 256 D) 256 C) 128 B) 64 A) 16 of b? equation is true for all values of x, what is the value In the given equation, a and b are constants. If the x-16x-a=x2-5ax+b