169 nm and the second-order diffraction angle is 41.0 degrees, we can use the equation for second-order diffraction:
\[ 2 \lambda = d \sin{\theta_2} \]
where:
\( \lambda \) = wavelength of the X-rays
\( d = 0.169 \) nm
\( \theta_2 = 41.0 \) degrees
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