X-rays diffract from a crystal in which the spacing between atomic planes is 0.171 nm. The second-order diffraction occurs at 41.0 degrees. What is the angle of the first-order diffraction?
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Step 1: Use Bragg's equation for the first order diffraction: \(2d \cos \theta = \lambda\), where \(n = 1\). Show more…
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X rays diffract from a crystal in which the spacing between atomic planes is $0.175 \mathrm{nm}$. The second-order diffraction occurs at $45.0^{\circ} .$ What is the angle of the first-order diffraction?
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