Question

$x^2y'' + xy' + (x^2 - \frac{1}{4})y = x^{3/2}$ $y_1 = x^{-1/2}\cos(x)$, $y_2 = x^{-1/2}\sin(x)$ $y(x) = $

Name: x2y xy x2 frac14y x32 y1 x 12cosx y2 x 12sinx yx 72961
Uploaded: 2019-08-01T22:05:47-08:00
Duration: 4 min 23 s
Channel: Roman Frolov
Description: x2y xy x2 frac14y x32 y1 x 12cosx y2 x 12sinx yx 72961

          $x^2y'' + xy' + (x^2 - \frac{1}{4})y = x^{3/2}$
$y_1 = x^{-1/2}\cos(x)$, $y_2 = x^{-1/2}\sin(x)$
$y(x) = $

$x2y xy x2 frac14y x32 y1 x 12cosx y2 x 12sinx yx 72961$

Added by Brandon G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Roman Frolov

08/01/2019

Step 1

The general solution is given by $y(x) = y_h(x) + y_p(x)$, where $y_h(x)$ is the homogeneous solution and $y_p(x)$ is the particular solution. Show more…

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