You have been sent an encoded message. Use the Linear Code, and the following clues to help you find the plaintext. Drag the correct answers into the boxes below The encoded message you were sent was ADUACH Clues - the letter D decodes to U and the letter U decodes to R. The decoding function is $D(x) = \text{ } \times \text{ } + \text{ }$ (mod 26) The plaintext is ABCDEFGHIJKL M 0 1 2 3 4 5 6 7 8 9 10 11 12 NOPQRSTUVWXYZ 13 14 15 16 17 18 19 20 21 22 23 24 25
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Let the decoding function be $D(x) = ax + b \pmod{26}$. Then we have the equations: $3a + b \equiv 20 \pmod{26}$ $20a + b \equiv 17 \pmod{26}$ Subtracting the first equation from the second gives: $17a \equiv -3 \equiv 23 \pmod{26}$ We need to find the Show more…
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Use technology to decode the message below that has been grouped before it was encoded. 34329 29485 31889 27745 32345 31961 29489 27949 13077 13157 31509 32757 27745 31557 31081 27945 13097 31945 13093 34693 33173 13085 29077 33077 27153 27945 a.) Write the decoded numerical message, using your decoding function b.) Use the Unicode table to assign letters to the corresponding number pairs in the decoded numerical message to produce the literal decoded message. The literal decoded message is:
Akash M.
Using the correspondence (1), we encoded the following message by a $2 \times 2$ matrix: $\left(\begin{array}{rrrrrrrrrrr}17 & 16 & 18 & 5 & 34 & 0 & 34 & 20 & 9 & 5 & 25 \\ -30 & -31 & -32 & -10 & -59 & 0 & -54 & -35 & -13 & -6 & -50\end{array}\right)$ Decode the message if its first two letters are DA and its last two letters are AY.
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You receive the following coded message today. (Read across from left to right.) $$ \begin{array}{lllllllllllllll} 47 & 95 & 7 & -1 & 43 & 7 & 79 & 43 & -1 & 75 & 55 & 67 & 31 & 71 & 75 & 27 \end{array} $$ $\begin{array}{lllllllllllll}15 & 23 & 67 & 15 & -1 & 75 & 15 & 71 & 75 & 75 & 27 & 31 & 51 & 23 & 71\end{array}$ $\begin{array}{llllllllllllll}31 & 51 & 7 & 15 & 71 & 43 & 31 & 7 & 15 & 11 & 3 & 67 & 15 & -1 & 11\end{array}$ Use the letter/number assignment described on the previous page to decode the message.
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