00:01
Here in this given problem there is a metal bar whose length that is given as 0 .650 meter.
00:23
It is moving with the uniform speed v is equal to 5 .0 meter per second perpendicular to a magnetic field 0 .750 tesla.
00:47
Resistance in the circuit that is 25 .0 ohm.
00:55
Here these are the two metal rails connected with each other with the resistance r whose value is 25 .0 ohm and this is the metal bar moving over the two rails with the velocity v.
01:17
And these are and this is the magnetic field uniform magnetic field directed into the plane of paper like this.
01:27
In the first part of the problem we have to find emf induced across the ends of this bar and that emf is given by the expression b v l product of magnetic field with the velocity and with the length of the metal bar.
01:52
For b this is 0 .750 multiplied by v which is 5 .0 multiplied by length which is 0 .650.
02:01
So, this emf is calculated to be equal to 2 .44 volt potential difference across the ends of the rod.
02:11
Answer for the first part of this given problem here.
02:15
In the second part of the problem we have to find direction of current induced and to find the direction of this current induced in the first method as the rod is moving rod and hence its free electrons are moving towards right.
03:15
So, electron will experience magnetic lorentz force in downward direction.
03:46
Downward means from end a of the metal bar to end b...