Question
A 1.50 -m-long metal bar is pulled to the right at a steady 5.0 $\mathrm{m} / \mathrm{s}$ perpendicular to a uniform, 0.750 -T magnetic field. The bar rides on parallel metal railsconnected through a $25.0-\Omega$ resistor, as shown in Fig. E29.28, so the apparatus makes a complete circuit. You can ignore the resistance of the bar and the rails. (a) Calculate the magnitude of the emf induced in the circuit.(b) Find the direction of the current induced in the circuit (i) using the magnetic force on the charges in the moving bar; (ii) using Faraday's law; (iii) using Lenz's law. (c) Calculate the current through the resistor.
Step 1
Substituting the given values, we get $E = (0.750 \, \text{T})(1.50 \, \text{m})(5.0 \, \text{m/s}) = 5.625 \, \text{V}$. Show more…
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A 1.50 -m-long metal bar is pulled to the right at a steady 5.0 $\mathrm{m} / \mathrm{s}$ perpendicular to a uniform, 0.750 - $\mathrm{T}$ magnetic field. The bar rides on parallel metal rails connected through a $25.0-\Omega$ resistor, as shown in $\mathrm{Fig}$ . 29.36 , so the apparatus makes a complete circuli. You can ignore the resistance of the bar and the rails. (a) Calculate the magnitude of the emf induced in the circuit. (b) Find the direction of the current induced in the circuit (i) using the magnetic force on the charges in the moving bar; (i) using Faraday's law; (iii) using Lenz's law. (c) Calculate the current through the resistor.
A 0.650-m-long metal bar is pulled to the right at a steady 5.0 m/s perpendicular to a uniform, 0.750 T magnetic field. The bar rides on parallel metal rails connected through a 25.0-$\Omega$ resistor ($\textbf{Fig. E29.30}$), so the apparatus makes a complete circuit. Ignore the resistance of the bar and the rails. (a) Calculate the magnitude of the emf induced in the circuit. (b) Find the direction of the current induced in the circuit by using (i) the magnetic force on the charges in the moving bar; (ii) Faraday's law; (iii) Lenz's law. (c) Calculate the current through the resistor.
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