00:01
So firstly to calculate the magnitude of the emf in the circuit, we know the emf empepsilon is equal to speed of the bar v times the magnetic field strength b and the length of the bar l.
00:18
We'll let a be directed into the figure so a clockwise emf is positive.
00:25
So these values are all known.
00:27
V is given as 5 meters per second and the magnetic field strength b is 0 .75 tesla's.
00:38
The length of the rod l is 1 .5 meters.
00:43
All our values in si units gives us an induced emf in the circuit of 5 .6 volts.
00:52
Next we want to calculate the direction of the induced current using three methods.
00:58
First method for the force law, if we let q be a positive charge in the moving.
01:03
Bar the magnetic force in this charge is given by the force law equation f is equal to q multiplied by v cross b and this force points upwards so f points upwards this force then pushes the current in a counterclockwise direction so using this method we see the current to be counterclockwise through the circuit.
01:37
The second method is using faraday's law.
01:40
So we know that the flux, phi magnetic flux, is positive and we also know that the flux is increasing...